x^2-3=(2+x)(3+x)

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Solution for x^2-3=(2+x)(3+x) equation: 



x^2-3=(2+x)(3+x)

We move all terms to the left:

x^2-3-((2+x)(3+x))=0

We add all the numbers together, and all the variables

x^2-((x+2)(x+3))-3=0

We multiply parentheses ..

x^2-((+x^2+3x+2x+6))-3=0



We calculate terms in parentheses: -((+x^2+3x+2x+6)), so:

(+x^2+3x+2x+6)

We get rid of parentheses

x^2+3x+2x+6

We add all the numbers together, and all the variables

x^2+5x+6

Back to the equation:

-(x^2+5x+6)



We get rid of parentheses

x^2-x^2-5x-6-3=0

We add all the numbers together, and all the variables

-5x-9=0

We move all terms containing x to the left, all other terms to the right

-5x=9

x=9/-5

x=-1+4/5

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